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Exercise 7.2

ใพใšใ€ไปปๆ„ใฎ pโ‰ค1p \leq 1 ใจ2ใคใฎใƒ™ใ‚ฏใƒˆใƒซ A=(a0,a1),B=(b0,b1)A = (a_0, a_1), B = (b_0, b_1) ใ‚’ใจใ‚‹ใ€‚
dpd_p ใฎๅฎš็พฉใ‚’2้€šใ‚Šใง่จˆ็ฎ—ใ™ใ‚‹ใ“ใจใง

dp(A,B)=(โˆฃa0โˆ’b0โˆฃp+โˆฃa1โˆ’b1โˆฃp)1pโ‰ค(2max(โˆฃa0โˆ’b0โˆฃ,โˆฃa1โˆ’b1โˆฃ)p)1p=21pmax(โˆฃa0โˆ’b0โˆฃ,โˆฃa1โˆ’b1โˆฃ)=21pdๅฐ†(A,B)โ†’pโ†’โˆždๅฐ†(A,B)\begin{aligned} d_p(A, B) &= ( |a_0 - b_0| ^ p + |a_1 - b_1| ^ p ) ^ {\frac{1}{p}} \\ &\leq ( 2 \text{max}(|a_0 - b_0|, |a_1 - b_1|) ^ p ) ^ {\frac{1}{p}} \\ &= 2 ^ {\frac{1}{p}} \text{max}(|a_0 - b_0|, |a_1 - b_1|) \\ &= 2 ^ {\frac{1}{p}} d_ๅฐ†(A, B) \xrightarrow{p\to\infty} d_ๅฐ†(A, B) \end{aligned}

ใจ้€†ๅ‘ใใฎไธ็ญ‰ๅทใฎๅผ

dp(A,B)=(โˆฃa0โˆ’b0โˆฃp+โˆฃa1โˆ’b1โˆฃp)1pโ‰ฅ(max(โˆฃa0โˆ’b0โˆฃ,โˆฃa1โˆ’b1โˆฃ)p)1p=max(โˆฃa0โˆ’b0โˆฃ,โˆฃa1โˆ’b1โˆฃ)=dๅฐ†(A,B)\begin{aligned} d_p(A, B) &= ( |a_0 - b_0| ^ p + |a_1 - b_1| ^ p ) ^ {\frac{1}{p}} \\ &\geq ( \text{max}(|a_0 - b_0|, |a_1 - b_1|) ^ p ) ^ {\frac{1}{p}} \\ &= \text{max}(|a_0 - b_0|, |a_1 - b_1|) \\ &= d_ๅฐ†(A, B) \end{aligned}

ใ‚’ๅพ—ใ‚‹ใ€‚

ไธŠ่จ˜ใ‚ˆใ‚Šใ€ dpโ†’pโ†’โˆždๅฐ†d_p \xrightarrow{p\to\infty} d_ๅฐ† ใงใ‚ใ‚‹ใ“ใจใŒใ‚ใ‹ใฃใŸใ€‚